College Math

3.7 Chapter Three Review Answers 1. c Solution: In this case, the measurement of side AB would be 5cm as the x-coordinate of A and B are same, means that the side AB is parallel to the y-axis. Now, substituting the value of height AB= 5cm in the formula for area for triangle, we can find the base BC. 25 = ½* 5*BC BC = 10 Now, the hypotenuse can be found by using the Pythagorean Theorem: AC 2 = BC 2 + AB 2 AC 2 =10 2 + 5 2 AC 2 = 125 AC = 5 √5 2. a Solution: Perimeter is the sum of all sides of a square. Since perimeter is 80, and all four sides of the square are equal, perimeter = 4*side 80 = 4*side Side of square = 20cm Area of square = side 2 = 20 2 = 400cm 2 3. d Solution: Perimeter of square = 4*side 32 = 4*side Side = 8cm Now, the diagonal of the rhombus divides the square into two right angle isosceles triangle, and the length of the diagonal can be found by using the Pythagorean Theorem where the two opposite sides of each triangle is 8cm each. Diagonal 2 = 8 2 + 8 2 Diagonal = 64 + 64 = 128 Diagonal = 8 √2 cm 4. d

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