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Alternative dose-response models

50

50

4

50

50

50

50

37

50

37

1

1

:)

(log

1 4 exp 1

1

:

942 .0

127 .0

,

1

exp

)2

(ln

exp

:

g

g

g

g

g





 

 

D

D

p dose

Logistic

D

D

p

Logistic

D

D

e

p

Poisson

D

D

p

=

1

2

p

exp

t

ò

(

-

x

2

)

dx

,

t

=

D

-

D

50

mD

50

LKB

g

50

=

1

m

2

p

Exercise: show this