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• Again, a set of differential equations results:

• Horrible, but applicable, solution:

)(

)(

)(

)(

)( )

( )(

)(

tCk tCk

dt

t

dC

tCk tCk k tCk

dt

t

dC

B 4

F 3

B

B 4

F 3

2

P 1

F

=

+

+ −

=

[

]

[

]

)(

)(

)(

)

(

)

(

)(

tC e e kk

tC

tC ek

e

k k

tC

P

t

t

1

2

31

B

P

t

4

2

t

1

4

1

2

1

F

2

1

2

1

=

− +

=

α

α

α

α

α

α

α

α

α

α

2

kk4 k k k

2

k k k

42

2

4

3

2

4

3

2

2 1

− + +

+ +

=

)

(

,

α

α