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3. Higher order of scatter
I have to repeat the method 2 times:
D
prim
→
S
1sc
→
CC with h
1sc
→
D
1sc
D
1sc
→
S
2sc
→
CC with H
msc
→
D
msc
•
The second step is approximate in that I
do not know the orientation of H
msc
I can assume it is isotropic or align it with
h
1sc
•
Calculation time increases to
(M
1sc
+M
msc
)N
3
•
Required M
msc
is < M
1sc
since the
gradient of D
1sc
is considerably less than
that of D
prim