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=

Σ

+ = 2.5Σ + 1.64

Σ = Σ

2

+ Σ

2

+ Σ

2

=

2

+

2

+

2

=

Σ

+ = 2.5Σ + 0.7 ′

′ =

2

+

2

′ cm

0.7 ′

1.64 ′

2

+ 0.32

2

− 0.32

A 5 mm distance between the

95% and 50% isodose surface

corresponds to

s

p

=3.2 mm