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loss plus static head loss, using Bernoulli’s Theorem of the

Law of Conservation of Energy where h

p

= (Z

b

– Z

a

) + ∑h

L

In our case, with a 2” diameter hose,

f

= 0,19

The slurry flow will give a friction loss of about 8,4 m

The Dynamic head on the pumps is then 8,4 + (3 – (-5))

= 16,4 m

Minus 5 m the suction height and 3 m being the discharge

height.

Pump selection

From the previously mentioned brochure, we can locate the

preliminary pump size from the location of the Discharge

rate of 4,75 L/sec and total head of 16,4 m as being a

2/1,5 B-AH slurry pump.

From the pump curve we can read off the Net Positive

Suction Head (NPSH

a

). We should now revisit the line losses

due to new fittings being introduced, eg, the 1,5” pump out-

let which will be enlarged to pipe size, but for our purposes

this will be ignored. While the selection seems adequate,

the small outlet diameter may be a problem with gravel. A

larger pump and increased production can be calculated

to allow a larger outlet pump size.

Equivalent water dynamic head

From theWeir Manual’s ‘Head ratio to efficiency ratio curves’

we can read off the HR/ER for and find HR/ER = 0,95

The equivalent head of water is therefore 16,4/0,95 = 17,26

of water.

Using a pump efficiency of 70 % from the pump curve,

we can calculate the power required to drive the pump

Brake HP = (gρ/1 000 x Q x h

p

) / eff = (9,81 x1 140/1 000 x

0,00475 x 17,26) / 0,7 = 1,31 kW.

Q = m

3

/sec , 1 000 = W/kW, h

p

= head loss in m, eff the

efficiency of the pump.

We would probably use a 4,5 kW diesel engine.

NPSH required at pump intake to avoid

cavitation

The NPSH required at any point on the pump curve is the

minimum net amount of energy of the actual mixture being

pumped above absolute zero pressure that the fluid must

have at the entrance to the impeller to avoid cavitation.

Slurry pumps fortunately do not exhibit the complete fall

off of the flow that classical water pumps exhibit when the

point is reached on the curve where cavitation commences

due to the high flow rate and consequential line losses. This

is most probably owing to the use of wide impellers and the

fact that vapour bubbles do not form across the whole width

of the impeller. The net positive head (NPH) at a point in the

pipeline is the absolute pressure head at that point, plus the

velocity head, less the vapour pressure. Reading a gauge

at a point in a pipeline, the NPH would be the gauge head

reading, plus atmospheric pressure head, minus the fluid

vapour pressure head, plus the velocity head. At the suction

inlet of the pump this is referred to as the NPSH and the

minimumNPSH required to avoid cavitation is shown on the

performance curve as NPSH required or NPSH

r

.

Net positive suction head available or

NPSH

a

To avoid cavitation (the phenomenon of formation of vapour

bubbles of a flowing liquid in a region, where the pressure

of the liquid falls below its vapour pressure), it is important

to compare the required NPSH (Net Positive Suction Head)

to the available NPSH.

From the system conditions and the liquid being pumped,

we can calculate the NPSH

a

and this must exceed the NPSH

r

to avoid cavitation. In practice, we are trying to avoid the

creation of vapour bubbles due to the pressure at the im-

peller being lower than the vapour pressure of the liquid,

which then creates bubbles.

NPSH

a

= H

atm

– H

vap

– Z

s

– H

i

– H

fs

H

atm

= Atmospheric pressure expressed in

metres of slurry

H

vap

= Absolute vapour pressure of the liquid

slurry carrier in metre of slurry

Z

s

= Static suction head, ie, the vertical height

PUMPS &

VALVESWW

25

Chemical Technology • April 2016