• Question 5: Which dose may be delivered to the
rectum in the 4 remaining fractions to not exceed
Rectum D
max
?
(α/β is assumed to be 3 for late toxicity)
•
Given:
Fraction 1(Rectum) Tolerance (Rectum)
- D
max
= 9,5 Gy
- D
max
= 42 Gy
- n = 1
- n = 5
- d = 9,5 Gy
- d = 8,4 Gy
Prostate cancer case