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• Question 5: Which dose may be delivered to the

rectum in the 4 remaining fractions to not exceed

Rectum D

max

?

(α/β is assumed to be 3 for late toxicity)

Given:

Fraction 1(Rectum) Tolerance (Rectum)

- D

max

= 9,5 Gy

- D

max

= 42 Gy

- n = 1

- n = 5

- d = 9,5 Gy

- d = 8,4 Gy

Prostate cancer case